Yield with odd first and last periods and settlement in first period.

Syntax

yld = yldoddfl(sd,md,id,fd,lcd,rv,price,cpn,per,basis,maxiter)
yld = yldoddfl(sd,md,id,fd,lcd,rv,price,cpn,per,basis)
yld = yldoddfl(sd,md,id,fd,lcd,rv,price,cpn,per)
yld = yldoddfl(sd,md,id,fd,lcd,rv,price,cpn)

Arguments

sd

Settlement date. Enter as serial date number or date string. sd must be earlier than or equal to md.

md

Maturity date. Enter as serial date number or date string.

id

Issue date. Enter as serial date number or date string.

fd

First coupon date. Enter as serial date number or date string.

lcd

Last coupon date. Enter as serial date number or date string.

rv

Redemption (par, face) value.

price

Price of the security.

cpn

Coupon rate. Enter as decimal fraction.

per

Coupons per year. An integer. Default = 2.

basis

Day-count basis: 0 = actual/actual (default), 1 = 30/360,
2 = actual/360, 3 = actual/365.

maxiter

Number of iterations used by Newton's method to solve for yld. Default = 50.

Description

Example

sd = '03/15/1993';
md = '03/01/2020';
id = '03/01/1993';
fd = '07/01/1993';
lcd = '01/01/2020';
rv = 100;
price = 95.71;
cpn = 0.04;
per = 2;
basis = 1;

yld = yldoddfl(sd,md,id,fd,lcd,rv,price,cpn,per,basis)

yld =
    0.0427 (or 4.27%)

See Also

Reference