Price with odd first and last periods and settlement in first period.

Syntax

[p, ai] = proddfl(sd, md, id, fd, lcd, rv, cpn, yld, per, basis)
[p, ai] = proddfl(sd, md, id, fd, lcd, rv, cpn, yld, per)
[p, ai] = proddfl(sd, md, id, fd, lcd, rv, cpn, yld)

Arguments

sd

Settlement date. Enter as serial date number or date string. sd must be earlier than or equal to md.

md

Maturity date. Enter as serial date number or date string.

id

Issue date. Enter as serial date number or date string.

fd

First coupon date. Enter as serial date number or date string.

lcd

Last coupon date. Enter as serial date number or date string.

rv

Redemption (par, face) value.

cpn

Coupon rate. Enter as decimal fraction.

yld

Yield. Enter as decimal fraction.

per

Coupons per year. An integer. Default = 2.

basis

Day-count basis: 0 = actual/actual (default), 1 = 30/360,
2 = actual/360, 3 = actual/365.

Description

Example

sd = '03/15/1993';
md = '03/01/2020';
id = '03/01/1993';
fd = '07/01/1993';
lcd = '01/01/2020';
rv = 100;
cpn = 0.04;
yld = 0.0427;
per = 2;
basis = 1;

[p, ai] = proddfl(sd, md, id, fd, lcd, rv, cpn, yld, per, basis)

p =
    95.6939
ai =
    0.1556

See Also

Reference